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Advanced Topics}Schwarzchild Radius

Using quite a bit of handwaving, the current author has seen an astrophysicist derive the Schwarzchild Radius (radius at which the curvature of space mooches and eats up light completely) via 1/2 m c^2 = G M m/r. (The guy totally neglected relativity, assuming that kinetic energy has the same form in the relativistic regime, but anyway...)

Handwaving like a good astrophysicist, one finds that r = 2 G M/c^2 \approx 2\times 7E-11 \times 6E24/9E16 = 1 cm.

(Note: the author is currently declared as an astrophysics major, and if the above comment is to be interpreted as pejorative towards astrophysicists, then she has thus implicitly insulted herself.)

See below for user comments and alternate solutions! See below for user comments and alternate solutions!
Alternate Solutions
scottopoly
2006-11-03 19:55:34
I once heard that if the Earth were compressed into a black hole, it would be about the size of a grape. I think that is a much faster solution. ;)Alternate Solution - Unverified
ben
2006-11-03 15:21:30
i've generally seen the schwarzchild radius derived from the escape velocity as shown in

http://scienceworld.wolfram.com/physics/SchwarzschildRadius.html
Alternate Solution - Unverified
Comments
ivalmian
2008-03-25 19:42:17
Um, well, the reason it's called the Schwarzschild radius is that it comes from Schwarzschild's solution of Einstein's equations. Take a look:

http://en.wikipedia.org/wiki/Deriving_the_Schwarzschild_solution
NEC
bat_pesso
2007-10-31 13:50:31
i don't think relativity is such an issue here, the escape velocity depends only on the mass of the earth, not on the mass of the particle.

thus 0.5c^2 is still GM/R
NEC
Jeremy
2007-10-18 13:17:00
Not having seen such hardcore hand waving before, I would not feel comfortable with this solution even if I had thought of it. Looking in my books afterwards, I found something that's pretty cool: you can get r \prop G M/c^{2} from dimensional analysis! (Of course you have to pick the right parameters.) And check this out, G M/c^{2}=4.4 mm, so unless the proportionality factor is several orders of magnitude, the closest answer is (C).

Moral: If thou needeth formulae, consulteth dimensional analysis. I think I gave up on this problem too quickly, when I could have at least submitted an educated guess.
NEC
chri5tina
2006-11-28 05:24:22
So in all this handwaving, did he explain the 1/2?
chri5tina
2006-11-28 05:32:11
well, I answered my own stupid question, however I'm hitting a bug when I try to edit my above post. I get this error when I try to edit:

omg are you trying to edit someone else's comment, you phisher?! (if you're innocent, then you ought to remember to login.)

when I am already logged in. and I'm not sure where to submit bugs.
Answered Question!
scottopoly
2006-11-03 19:55:34
I once heard that if the Earth were compressed into a black hole, it would be about the size of a grape. I think that is a much faster solution. ;)Alternate Solution - Unverified
ben
2006-11-03 15:21:30
i've generally seen the schwarzchild radius derived from the escape velocity as shown in

http://scienceworld.wolfram.com/physics/SchwarzschildRadius.html
Alternate Solution - Unverified
pablojm
2006-10-28 15:30:36
This is a good argument to convince someone who doesn't know physics, but how do you know it works...?
evanb
2008-07-01 17:22:24
Unfortunately, the way would know it works is by doing the general relativity. You can deduce that in the Schwarzschild metric for a point mass, any timelike or null (lightlike) trajectory (ie. any trajectory that a particle might take) that starts within R = 2M will ever wind up outside of R = 2M ( G = c = 1).

Un-unfortunately, GR reproduces lots of "Newtonian" results. You can even do most cosmology with Newtonian math. Why does that work? Because someone did it fully-general-relativistically and found that the math wound up the same...
Answered Question!

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