GREPhysics.NET: GR8677 #19

GR8677 #19

Problem

GREPhysics.NET Official Solution

Alternate Solutions

Quantum Mechanics $\Rightarrow$ }Bohr Theory

Recall the Rydberg energy. QED

Alternate Solutions

casseverhart13 2019-10-01 03:22:05	Good Examine and fascinating. Thanks. www.trustytreeservice.com Reply to this comment
jeka 2007-02-17 08:08:36	Energy spectrum of the hydrogen atom is given by the equation $E_n=-\frac{Ry}{n^2}$ , where $Ry=13.6\rm{eV}$ is the Rydberg constant. So the right answer is (E) Reply to this comment

Comments

casseverhart13
2019-10-01 03:22:05

Good Examine and fascinating. Thanks. www.trustytreeservice.com

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ernest21
2019-08-10 03:09:33

Instead of doing the long division by hand, you could just say that gamma is less than 2. Solving the inequality you get that v > \\sqrt{3/4}c. E is the only answer that satisfies this. amino acid game

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joshuaprice153
2019-08-08 07:30:34

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jeka
2007-02-17 08:08:36

Energy spectrum of the hydrogen atom is given by the equation

$E_n=-\frac{Ry}{n^2}$ ,

where $Ry=13.6\rm{eV}$ is the Rydberg constant. So the right answer is (E)

FortranMan
2008-10-16 23:10:09

According to Griffiths, the allowed energies for a hydrogen atom are

$E_{n} = -\left[ \frac{m}{2 \hbar^2} \left(\frac{e^2}{4 \pi \epsilon_{0}}\right)^{2}\right] \frac{1}{n^2} = \frac{E_1}{n^2}$

Where $E_{1}$ is the ground state of the hydrogen atom,

$E_{1} = 13.6 eV$

The Rydberg constant is defined as

$R_{y} = \left[ \frac{m}{4 \pi c \hbar^3}\left(\frac{e^2}{4 \pi \epsilon_{0}}\right)^{2}\right] = 1.097 \times 10^{7} m^{-1}$

Thus the energy levels are given as

$E_{n} = - \frac{2 \pi c \hbar R_y}{n^2}$

Not entirely necessary to solve the problem, but it's safer to keep your terms straight.

VKB
2014-03-25 21:44:48

Its a good approach to solve problems @ home,interesting.

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