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GR8677 #19
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Problem
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Quantum Mechanics }Bohr Theory
Recall the Rydberg energy. QED
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Alternate Solutions |
casseverhart13
2019-10-01 03:22:05 | Good Examine and fascinating. Thanks. www.trustytreeservice.com |  | jeka
2007-02-17 08:08:36 | Energy spectrum of the hydrogen atom is given by the equation
 ,
where  is the Rydberg constant. So the right answer is (E) | |
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Comments |
casseverhart13
2019-10-01 03:22:05 | Good Examine and fascinating. Thanks. www.trustytreeservice.com | | ernest21
2019-08-10 03:09:33 | Instead of doing the long division by hand, you could just say that gamma is less than 2. Solving the inequality you get that v > \\sqrt{3/4}c. E is the only answer that satisfies this. amino acid game |  | joshuaprice153
2019-08-08 07:30:34 | I\'m definitely going to bookmark your site, I just love your post, thanks for such a nice sharing.. Hope to get some info on your site in future. carpet steam cleaner | | jeka
2007-02-17 08:08:36 | Energy spectrum of the hydrogen atom is given by the equation
,
where is the Rydberg constant. So the right answer is (E)
FortranMan
2008-10-16 23:10:09 |
According to Griffiths, the allowed energies for a hydrogen atom are
![E_{n} = -\left[ \frac{m}{2 \hbar^2} \left(\frac{e^2}{4 \pi \epsilon_{0}}\right)^{2}\right] \frac{1}{n^2} = \frac{E_1}{n^2}](/cgi-bin/mimetex.cgi?E_{n} = -\left[ \frac{m}{2 \hbar^2} \left(\frac{e^2}{4 \pi \epsilon_{0}}\right)^{2}\right] \frac{1}{n^2} = \frac{E_1}{n^2} )
Where  is the ground state of the hydrogen atom,
The Rydberg constant is defined as
![R_{y} = \left[ \frac{m}{4 \pi c \hbar^3}\left(\frac{e^2}{4 \pi \epsilon_{0}}\right)^{2}\right] = 1.097 \times 10^{7} m^{-1}](/cgi-bin/mimetex.cgi?R_{y} = \left[ \frac{m}{4 \pi c \hbar^3}\left(\frac{e^2}{4 \pi \epsilon_{0}}\right)^{2}\right] = 1.097 \times 10^{7} m^{-1})
Thus the energy levels are given as
Not entirely necessary to solve the problem, but it's safer to keep your terms straight.
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VKB
2014-03-25 21:44:48 |
Its a good approach to solve problems @ home,interesting.
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