GREPhysics.NET: GR8677 #16

GR8677 #16

Problem

GREPhysics.NET Official Solution

Advanced Topics $\Rightarrow$ }Particle Physics

The properties of a muon most closely resembles that of an electron. In the usual $\beta$ -decay, an electron is emitted along with either a neutrino or an antineutrino. In a wildcard $\beta$ -decay, a muon is emitted instead of an electron.

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Comments

ernest21 2019-08-10 03:09:29	Your your equation is well solved. upcoming fighting games Reply to this comment
joshuaprice153 2019-08-08 07:17:05	I am not positive the place you\'re getting your info, but good topic. I needs to spend a while finding out more or working out more. Thanks for excellent information I was looking for this information for my mission. tree pruning Reply to this comment
chemicalsoul 2009-11-01 08:18:31	haha thats a really good use of the word Wildcard ! I like it. Reply to this comment
justmax 2009-10-19 19:32:29	Muons are leptons: A) electrons are leptons B) & C) graviton and photon are force mediating particles (bosons) D) Pions are quarks (a quark and an antiquark) E) Protons are a trio of quarks. A) fits best. Reply to this comment
sonnb 2007-05-20 02:08:40	A muon has charge -1 and spin 1/2. An electron has charge -1 and spin 1/2. A graviton has charge 0 and spin 2. A photon has charge 0 and spin 1. A pion has either charge +1 or 0 and spin 0. A proton has charge +1 and spin 1/2. With these criteria, the electron most closely resembles the properties of the electron. From Vol 2 of H/R/K. Reply to this comment
comorado 2006-10-23 12:39:26	I would say that muon is a partical from Lepton group so are electron, tauon, neutrino. So the answer must be (A). Reply to this comment

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I would say that muon is a partical from Lepton group so are electron, tauon, neutrino. So the answer must be (A).

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