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Giubenez
2014-10-22 02:55:55 | Nice bad pics:
the trend for x>R isn't an inverse square (if you estimate for E(x=2R)/E(R) you find 1/2 and not 1/4.
Furthermore it seems to have an horizontal asymptote > 0......
And so, all the graph are wrong. | |
flyboy621
2010-11-09 20:54:39 | A minor correction: the field increases linearly with the radius of the sphere, not the volume. Hence the straight line of graph C.
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nmast
2009-11-24 09:16:37 | Since the charge density is uniform, shouldn't E go like Q enclosed? Being a sphere, this would be like r^3, making D correct.
kroner
2009-11-27 19:08:54 |
No. Q is proportional to  , but E is proportional to  which means E is linear in r, as in choice C.
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wittensdog
2009-09-24 21:45:16 | ETS sure does love to throw in unnecessary details - who cares if the charge is positive or negative when it comes to the field magnitude? | |
Andresito
2006-03-14 22:37:41 | Gauss' law E*A = Q/epsilon
Yours is an approximation.
Thanks Yosun.
lxanderl
2009-06-28 17:23:43 |
Depends on if he's using cgs or SI
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