GR9277 #41
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Alternate Solutions |
Ryry013 2019-10-06 09:10:04 | A slightly faster way to do this problem is to know that if omega halves, then kinetic energy will decrease by 1/4. Then energy LOST is just (0.5)(4)(80^2) * (3/4) = (0.5)(6400)(3/4) = 9600J |  |
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Comments |
Ryry013 2019-10-06 09:10:04 | A slightly faster way to do this problem is to know that if omega halves, then kinetic energy will decrease by 1/4. Then energy LOST is just (0.5)(4)(80^2) * (3/4) = (0.5)(6400)(3/4) = 9600J |  | mnky9800n 2013-09-24 13:05:47 | I also like to think in terms of the potential energy of a 100kg person who is about to fall 10 meters. That is mgh~(100 kg)(10 m/s^2)(10 m) = 10000 J. Thus A and B are probably too small and E is probably too big. |  | aloha 2008-10-10 03:21:51 | Maybe it's a silly question, but how can we know that I=4?
Thanks :)
Monk 2008-10-13 20:11:46 |
it tells you in the question...it is 4 kg m^2
kg m^2 is the units not a formula
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tensordyne 2008-11-04 13:16:28 |
I am with Monk, from reading the problem it seems like they are saying is a formula in k (proportionality factor maybe), g ( ) and mass m instead of as units because there is no grouping of the units, such as in say , which would have made the use of units much more manifest.
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