|
GR9277 #1
|
|
|
|
|
Alternate Solutions |
casseverhart13
2019-07-04 10:57:43 | Thanks for your post! electrical contactor\r\n |  | tera
2006-08-21 02:14:34 | You can get the result by dimentional analysis | |
|
|
Comments |
casseverhart13
2019-07-04 10:57:43 | Thanks for your post! electrical contactor\r\n | | deepblue
2013-03-04 18:35:26 | This website is great.
I was wondering if there was a possible miscalculation.
It appears using the momentum operator normally defined you would have
-(i)*(i)hk which leads to an imaginary number times an imaginary number which is -1 .
So you have - [(i)*(i)] = (-)(-1)hk. So you get answer (C) which is just hk.
=================================================
(My point is the author divided by (i) in the definition of the momentum operator instead of multipling the two imaginary numbers)
zeper
2013-03-09 09:11:39 |
no there is no mistake...1/i means -i...which is the same notation you mensioned.
|
|  | grep
2006-10-30 13:28:58 | You can also recognize that the wave function is just a standard transverse wave (like a light wave) for which de Broglie tells us h=lambda*p and the propagation number tells us k=2 pi/lambda
roofsing
2010-06-21 23:37:57 |
|
| | grep
2006-10-03 12:37:48 | Oops, I meant it also leaves choice D
BerkeleyEric
2010-05-31 15:18:12 |
(D) actually gives units of kg * m/s^2, not kg * m^2/s as needed. (A) cannot be eliminated from dimensional analysis, but from physical intuition we know that a wave traveling in the x-direction should have momentum in the x-direction.
|
| | grep
2006-08-28 13:07:27 | Hmm, doesn't dimensional analysis leave C as a possible choice? (or A for that matter)
gina4eva
2011-11-10 18:10:14 |
but isn't c the answer?
|
| | tera
2006-08-21 02:14:34 | You can get the result by dimentional analysis
alemsalem
2010-09-24 08:30:20 |
the units for choice D also work but we dont know that the particle is moving with speed of light.
|
Quark
2011-10-25 12:04:21 |
More accurately, the particle can't be moving at the speed of light.
|
myscifilullaby1
2012-03-08 17:32:19 |
indeed! dimensional analysis gives two possibilities, A & C. When you use the momentum operator, you get C as the final answer.
|
| | gottlob
2006-06-13 12:18:50 | I am a physics teacher from Greece and am trying to download the gre.pdf forms of the gre tests. I have downloaded the GRE0177 but i can't get the others (GRE9677, GRE9277 etc. My e-mail is nchalk@phs.uoa.gr. Please, if any one can sent me, or give me information about, the tests i would be gratefull to him. | |
|
| Post A Comment! |
|
|
Bare Basic LaTeX Rosetta Stone
|
LaTeX syntax supported through dollar sign wrappers $, ex., $\alpha^2_0$ produces  .
|
| type this... |
to get... |
| $\int_0^\infty$ |
 |
| $\partial$ |
 |
| $\Rightarrow$ |
 |
| $\ddot{x},\dot{x}$ |
 |
| $\sqrt{z}$ |
 |
| $\langle my \rangle$ |
 |
| $\left( abacadabra \right)_{me}$ |
_{me}) |
| $\vec{E}$ |
 |
| $\frac{a}{b}$ |
 |
|
|
|
|
The Sidebar Chatbox...
Scroll to see it, or resize your browser to ignore it... |
|
|
|
