|
Atomic }Positronium
Interestingly, this is almost an exact repeat of Exam 9677 Prob 12. The reasoning's the same:
The positronium atom involves a positron-electron combination instead of the usual proton-electron combo for the H atom. Charge remains the same, and thus one can approximate its eigenvalue by changing the mass of the Rydberg energy (recall that the ground state of the Hydrogen atom is 1 Rydberg).
Recall the reduced mass , where for identical masses, one obtains . The Rydberg in the regular Hydrogen energy eigenvalue formula is , where . Substitute in the new value of the reduced mass to get . eV, and thus eV.
|