GREPhysics.NET: GR8677 #58

GR8677 #58

Problem

GREPhysics.NET Official Solution

Optics $\Rightarrow$ }Holograms

A hologram is produced from interference of light. Interference of two-beams (one going directly to the film, the other bouncing off the object) produced by a beam-splitter allows the film to record both intensity and relative phase of the light at each point. Intensity (to wit: $I\propto E_0^2 \langle \sin^2 \omega t \rangle=E_0^2/2$ ) does not depend on angular frequency, but only on phase and amplitude. Thus, choice (B) is right.

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Comments

FortranMan
2008-10-27 17:25:59

how can intensity depend on phase if $\langle cos^{2} \rangle = \langle sin^{2} \rangle$ ?

a19grey2
2008-11-03 22:37:32

Intensity depends on phase in single and double slit diffraction experiments. I suggest reading up on these experiments as an introduction to phase relationships.

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evanb
2008-06-20 13:21:53

Just the fact that if you've ever looked at a hologram you can tell that it doesn't retain the color information should rule out III.

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ELC
2007-10-23 18:08:33

Also, doesn't the "monochromatic light" comment tip you off that it's not III. Isn't "wave-front angular frequency" just the color of the light?

a19grey2
2008-11-03 22:36:32

Yes, this is why III is not part of the right answer.
There are holograms (freaking awesome ones) that use polychromatic light and thus record information using I, II, and III. The key here though, is the term monochromatic.

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