GREPhysics.NET
GR | # Login | Register
   
  GR0177 #49
Problem
GREPhysics.NET Official Solution    Alternate Solutions
This problem is still being typed.
Statistical Mechanics}Partition Functions

The partition function is given by the formula Z=\sum_i g_i e^{-\epsilon_i/kT}, where g_i enotes the degeneracy of the ith state.

Plug in the given information into the formula to get choice (E).

See below for user comments and alternate solutions! See below for user comments and alternate solutions!
Alternate Solutions
There are no Alternate Solutions for this problem. Be the first to post one!
Comments
duckduck_85
2008-10-30 22:44:09
I think it might be important to note that ETS is using the term "Maxwell-Boltzmann distribution" indistinctively from "Canonical Distribution" in this problem. Even though they do have the same mathematical form, i think it might be more appropriate to refer to this system as a system following a canonical distribution.
thatoneguy
2011-11-08 05:46:49
Old comment, but I don't think that's necessarily true. The Canonical Distribution doesn't have degeneracies. IIRC, it's of the form Z = \sum_{i} \e^{\frac{-\epsilon_{i}}{kT} . In particular, the distribution for an MB system can have degeneracies, unlike those systems which follow Fermi-Dirac statistics (which still follow the Canonical Distribution function. I believe they are using "Maxwell-Boltzmann Distribution" distinctively in this case.
4elesta
2012-04-15 15:23:49
Please, can someone explain, why it's said that distribution is Maxwellian? thanks)
ETScustomer
2017-10-10 18:53:57
Maxwell also did great thermal work.
NEC

Post A Comment!
Username:
Password:
Click here to register.
This comment is best classified as a: (mouseover)
 
Mouseover the respective type above for an explanation of each type.

Bare Basic LaTeX Rosetta Stone

LaTeX syntax supported through dollar sign wrappers $, ex., $\alpha^2_0$ produces .
type this... to get...
$\int_0^\infty$
$\partial$
$\Rightarrow$
$\ddot{x},\dot{x}$
$\sqrt{z}$
$\langle my \rangle$
$\left( abacadabra \right)_{me}$
$\vec{E}$
$\frac{a}{b}$
 
The Sidebar Chatbox...
Scroll to see it, or resize your browser to ignore it...