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Welcome to GRE Physics Solutions. This is where you'll find complete in-depth solutions to all problems from the ETS released GRE Advanced Physics Examinations.

Free solutions, always and forever. The site aims to provide the most comprehensive and easy-to-access source of solutions to released GRE Physics exams.

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1-liner: Jump directly to a particular problem via the QuickLoad bar. (On the grey bar on top of the page, you can quickly jump to a problem by selecting GRxxxx, Problem y.)

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Alternate solutions are contributed by users like you in the comments section appending each problem. Your questions pertaining to a particular problem are, in turn, answered by other users. If you find any errors or have an alternate solution you'd like to share---feel free to post a comment!

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Top 10 latest comments:

1	Exam GR0177; Problem 81; Page 0 Posted by jmason86, on 2009-07-03 15:08:49.
	How did you know to use 6? The problem said to use 3S and there are 2 electrons. 3 = 2s+1, which can be solved for spin. But where does the 6 come from?           jump to this problem
2	Exam GR0177; Problem 51; Page 0 Posted by jmason86, on 2009-07-03 14:27:44.
	Conceptually this is really weird. The first filter cuts the light in half, which makes sense. You could imagine that all the light is now, say, vertical. The second filter is at 45 degrees, but the light is already vertical, so this should just reduce the intensity. The last filter is at 90 degrees from the first, so it should only allow horizontal light through, but there is none... it's all vertical. So I would expect no light to be transmitted through this filter. The math works out fine, but I cant imagine how this works physically.           jump to this problem
3	Exam GR0177; Problem 41; Page 0 Posted by jmason86, on 2009-07-03 14:13:30.
	Magnetic monopoles*           jump to this problem
4	Exam GR9677; Problem 73; Page 0 Posted by gt2009, on 2009-07-03 12:35:10.
	C is a constant so you can pull it out of the integral. It is not ignoring anything.           jump to this problem
5	Exam GR0177; Problem 90; Page 0 Posted by edhopkins, on 2009-06-28 19:48:12.
	Is it accurate to stake the assumption that both the effective spring constant adds in parallel and the distance traveled is half? It seems like one ought to come from the other. If you ignore the distance traveled you can still arrive at the ratio of periods purely by = . Offhand it seems that by inspection one could assume the distance traveled by the two springs in series is twice that of those in parallel, and intuitively reach the same conclusion.           jump to this problem
6	Exam GR0177; Problem 89; Page 0 Posted by edhopkins, on 2009-06-28 19:28:42.
	Actually the child will need to maintain friction not overcome it, or else he will discover quickly what the jedi mind force can do to his/her trajectory. It seems to me that the original approach works because it is constrained motion (pin on the center of the large disk). Now what if it were say a section of the space station rotating in space with the child as an astronaut?           jump to this problem
7	Exam GR8677; Problem 10; Page 0 Posted by lxanderl, on 2009-06-28 17:23:43.
	Depends on if he's using cgs or SI           jump to this problem
8	Exam GR9677; Problem 8; Page 0 Posted by gt2009, on 2009-06-28 13:20:30.
	Both periods are constant, but the damped period is greater than the undamped period.           jump to this problem
9	Exam GR8677; Problem 90; Page 0 Posted by gt2009, on 2009-06-25 17:17:22.
	2 antinodes, not nodes           jump to this problem
10	Exam GR8677; Problem 81; Page 0 Posted by gt2009, on 2009-06-25 16:38:29.
	It said approximately equal to.           jump to this problem